Assay
Internal standard solution
Dissolve a quantity of biphenyl in chloroform to obtain a solution containing about 20 mg per mL.
Standard preparation
Transfer about 170 mg of
USP Terpin Hydrate RS, accurately weighed, to a 100-mL volumetric flask, dissolve in 5 mL of alcohol, add 5.00 mL of
Internal standard solution, dilute with chloroform to volume, and mix.
Assay preparation
Transfer about 170 mg of Terpin Hydrate, accurately weighed, to a 100-mL volumetric flask, and proceed as directed under Standard preparation, beginning with dissolve in 5 mL of alcohol.
Chromatographic system
Under typical conditions, the gas chromatograph is equipped with a flame-ionization detector, and it contains a 3.5-mm × 1.2-m glass column packed with 6% G1 on support S1A; the injection port and the detector temperatures are maintained at 260
, and the column temperature at 120
; and nitrogen is used as the carrier gas, at a flow rate necessary to yield approximate retention times of 7 minutes for terpin and 11 minutes for biphenyl.
System suitability test
Chromatograph the Standard preparation, and record the chromatograms as directed for Procedure: the resolution, R, between the terpin and biphenyl peaks is not less than 2.0, and the relative standard deviation for replicate injections is not more than 2.0%.
Procedure
Inject about 1 µL of the
Standard preparation into a suitable gas chromatograph, and record the chromatogram. Similarly, inject about 1 µL of the
Assay preparation, and record the chromatogram. Calculate the quantity, in mg, of C
10H
20O
2 in the portion of Terpin Hydrate taken by the formula:
WS(RU / RS),
in which
WS is the weight, in mg, of
USP Terpin Hydrate RS, calculated on the anhydrous basis; and
RU and
RS are the area-ratios of terpin to the internal standard obtained from the chromatograms for the
Assay preparation and the
Standard preparation, respectively.