Chromatographic purity
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Transfer about 200 mg of Famotidine, accurately weighed, to a 10-mL volumetric flask, add 2 mL of methanol, and shake for 10 minutes. Add 0.1 mL of glacial acetic acid, stir until dissolved, dilute with methanol to volume, and mix.
Standard solutions
Dissolve an accurately weighed portion of
USP Famotidine RS in a mixture of methanol and glacial acetic acid (100:1) to obtain
Standard solution 1 having a known concentration of 0.2 mg per mL. Dilute a portion of this solution, accurately measured, with a mixture of methanol and glacial acetic acid (100:1) to obtain
Standard solution 2 containing 65 µg of
USP Famotidine RS per mL.
Developing solvent system:
a mixture of ethyl acetate, methanol, toluene, and ammonium hydroxide (40:25:20:2).
Procedure
Separately apply 5 µL of the
Test solution and 5 µL of each
Standard solution to a plate, and dry under a stream of nitrogen. Proceed as directed for
Thin-Layer Chromatography under
Chromatography 621. Examine the plate under short-wavelength UV light, and compare the intensities of any secondary spots observed in the chromatogram of the
Test solution with those of the principal spots in the chromatograms of the
Standard solutions: no secondary spot from the chromatogram of the
Test solution is larger in size or more intense than the principal spot obtained from
Standard solution 2 (0.3%); and the sum of the intensities of the secondary spots obtained from the
Test solution corresponds to not more than 1.0%
(Standard solution 1).
Assay
Dissolve about 250 mg of Famotidine, accurately weighed, in 80 mL of glacial acetic acid, and titrate with 0.1 N perchloric acid VS (see
Titrimetry 541), using a suitable anhydrous electrode system. Any aqueous electrolyte solution contained in the electrodes employed should be removed, the electrode rendered anhydrous and filled with 0.1 N lithium perchlorate in acetic anhydride. Perform a blank determination and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 16.87 mg of C
8H
15N
7O
2S
3.