Packaging and storage—
Preserve in well-closed containers.
Labeling—
Label Solution to state the solvent used and the claimed concentration of anhydrous aluminum dichlorohydrate contained therein.
Identification—
A:
A solution containing the equivalent of about 100 mg of anhydrous aluminum dichlorohydrate per mL responds to the tests for
Aluminum 
191
and for
Chloride 191.
Test specimen—
Add about 10 mL of isopropyl alcohol to 2 g of Solution, mix, and filter. Evaporate the filtrate to about 1 mL on a steam bath. Deposit this solution on a silver chloride disk.
Standard specimen:
a similar preparation of propylene glycol.
Test specimen—
Add about 10 mL of isopropyl alcohol to 2 g of Solution, mix, and filter. Evaporate the filtrate to about 1 mL on a steam bath. Deposit this solution on a silver chloride disk.
Standard specimen:
a similar preparation of dipropylene glycol.
D:
Identification of alcohol (where stated on the label)—Mix 5 drops of Solution in a small beaker with 1 mL of potassium permanganate solution (1 in 100) and 5 drops of 2 N sulfuric acid, and cover the beaker immediately with filter paper moistened with a freshly prepared solution of 0.1 g of sodium nitroferricyanide and 0.25 g of piperazine in 5 mL of water: an intense blue color is produced on the filter paper, the color becoming paler after a few minutes.
pH 791:
between 3.0 and 5.0, in a solution prepared by diluting 3 g of the Solution with water to obtain 10 mL.
Arsenic, Method I 211—
Prepare the
Test Preparation using an accurately weighed quantity of the Solution. The limit is 2 µg per g.
Heavy metals, Method I 231—
Prepare the
Test Preparation using an accurately weighed quantity of the Solution. The limit is 10 µg per g.
Aluminum/chloride atomic ratio—
Divide the percentage of aluminum found in the test for
Content of aluminum by the percentage of chloride found in the test for
Content of chloride, and multiply by 35.453/26.98, in which 35.453 and 26.98 are the atomic weights of chlorine and aluminum respectively: the ratio is between 0.90:1 and 1.25:1.
Assay—
Calculate the percentage of anhydrous aluminum dichlorohydrate in the Solution by the formula:
Al({26.98
x + [17.01(3
x 
1)] + 35.453} / 26.98
x),
in which
Al is the percentage of aluminum found in the test for
Content of aluminum,
x is the aluminum/chloride atomic ratio found in the test for
aluminum/chloride atomic ratio, 26.98 is the atomic weight of aluminum, 17.01 is the molecular weight of the hydroxide anion (OH), and 35.453 is the atomic weight of chlorine (Cl).
