Packaging and storage—
Preserve in well-closed containers.
Labeling—
The label states the content of anhydrous aluminum zirconium trichlorohydrate.
Identification—
A solution (1 in 10) responds to the test for
Chloride 
191
.
pH 791:
between 3.0 and 5.0, in a solution [15 in 100 (w/w)].
Heavy metals, Method I 231—
Proceed as directed in the chapter, except to use the following modifications.
Test Preparation—
Prepare as directed in the chapter. If the solution is not clear after dilution to 40 mL, heat for several minutes between 60
and 80
, and cool to room temperature. If the solution remains cloudy, repeat from the beginning with the following modification: add 3 mL of hydrochloric acid prior to adjustment of the pH with 6 N ammonium hydroxide.
Monitor Preparation—
Prepare as directed in the chapter, using the same modifications described for Test Preparation if necessary.
Procedure—
To each of the three tubes containing the
Standard Preparation, the
Test Preparation, and the
Monitor Preparation, add 2 mL of
pH 3.5 Acetate Buffer, and heat gently to between 60
and 80
. To the
Standard Preparation add 6 drops of
sodium sulfide TS. To the
Test Preparation and the
Monitor Preparation add 12 drops of
sodium sulfide TS. Cool to room temperature, and dilute the contents of each tube with water to 50 mL. Gently mix each tube by inverting twice. Allow to stand for 5 minutes, and view downward over a white surface. The color of the solution from the
Test Preparation is not darker than that of the solution from the
Standard Preparation, and the color of the solution from the
Monitor Preparation is the same as or darker than the color of the solution from the
Standard Preparation. If the color of the solution from the
Monitor Preparation is lighter than the color of the solution from the
Standard Preparation, repeat the procedure with the following modification: after the heating step, to the
Monitor Preparation and the
Test Preparation add 1.0 mL, instead of 12 drops, of
sodium sulfide TS. Not more than 20 µg per g is found.
Limit of iron—
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate, proceed as directed in the test for
Limit of iron under
Aluminum Zirconium Octachlorohydrate. The specified result is obtained (150 µg per g limit).
Content of aluminum—
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate, proceed as directed in the test for
Content of aluminum under
Aluminum Zirconium Octachlorohydrate. Use the result obtained to calculate the
Aluminum/
zirconium atomic ratio and the (
Aluminum plus zirconium)/
chloride atomic ratio.
Content of zirconium—
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate, proceed as directed in the test for
Content of zirconium under
Aluminum Zirconium Octachlorohydrate. Use the result obtained to calculate the
Aluminum/
zirconium atomic ratio and the (
Aluminum plus zirconium)/
chloride atomic ratio.
Aluminum/zirconium atomic ratio—
Divide the percentage of aluminum found in the test for Content of aluminum by the percentage of zirconium found in the test for Content of zirconium, and multiply by 92.97/26.98, in which 92.97 is the atomic weight of zirconium corrected for 2% hafnium content, and 26.98 is the atomic weight of aluminum: the ratio is between 2.0:1 and 5.99:1.
Content of chloride—
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate, proceed as directed in the test for
Content of chloride under
Aluminum Zirconium Octachlorohydrate. Use the result obtained to calculate the (
Aluminum plus zirconium)/
chloride atomic ratio.
(Aluminum plus zirconium)/chloride atomic ratio—
Calculate the (aluminum plus zirconium)/chloride atomic ratio by the formula:
[(Al/26.98) + (Zr/92.97)]/(Cl/35.453),
in which
Al,
Zr, and
Cl are the percentages of aluminum, zirconium, and chloride as determined in the tests for
Content of aluminum,
Content of zirconium, and
Content of chloride, respectively; 26.98 is the atomic weight of aluminum; 92.97 is the atomic weight of zirconium corrected for 2% hafnium content; and 35.453 is the atomic weight of chlorine: the ratio is between 2.1:1 and 1.51:1.
Assay—
Calculate the percentage of anhydrous aluminum zirconium trichlorohydrate in the Aluminum Zirconium Trichlorohydrate by the formula:
Al({26.98
y + 92.97 + 17.01[3
y + 4
(
y + 1)/
z] + 35.453(
y + 1)/
z}/26.98
y),
in which
Al is the percentage of aluminum found in the test for
Content of aluminum,
y is the aluminum/zirconium atomic ratio found in the test for
Aluminum/
zirconium atomic ratio,
z is the (aluminum plus zirconium)/chloride atomic ratio found in the test for (
Aluminum plus zirconium)/
chloride atomic ratio, 26.98 is the atomic weight of aluminum, 92.97 is the atomic weight of zirconium corrected for 2% hafnium content, 17.01 is the molecular weight of the hydroxide anion (OH), and 35.453 is the atomic weight of chlorine (Cl).
